Infinite sequence of functions \(f_i\), \(i = k, k+1, \dots\)
All defined on a common domain \(D\).
For each \(x \in D\) we get a sequence \(f_i(x)\), \(i = k, k+1, \dots\)
Is this sequence convergent?
If it is, what is the \(\displaystyle\lim_{i\to\infty} f_i(x)\)?
Let \(E\) be the set of all \(x\in D\) such that \(\displaystyle\lim_{i\to\infty} f_i(x)\) exists.
Limit of Sequence
Let \(E\) be the set of all \(x\in D\) such that \(\displaystyle\lim_{i\to\infty} f_i(x)\) exists.
Define a function \(f\) with domain \(E\): \[f(x) = \lim_{i\to\infty} f_i(x)\]
We say that the function \(f\) is the limit of the sequence \((f_i)_{i = k, k+1,
\dots}\), or that the sequence \((f_i)\) converges to \(f\) on the set \(E\).
Example
Example
\(f_i(x) = x^i\) for \(i = 1, 2, \dots\)
If \(-1 < x < 1\), \(\displaystyle\lim_{i\to\infty}f_i(x) = 0\).
If \(x = 1\), \(\displaystyle\lim_{i\to\infty}f_i(x) = 1\).
If \(x \le -1\) or \(1 < x\), \(\displaystyle\lim_{i\to\infty}f_i(x)\) does not exist.
\[f(x) = \begin{cases} 0 & \text{ if $-1 < x < 1$}\\1 & \text{ if $x =
1$}\end{cases}\]
The sequence \((f_i)\) converges to \(f\) on \((-1,1]\).
Another Example
Another Example
\(f_i(x) = e^{-ix^2}\) for \(i = 1, 2, \dots\)
If \(x \neq 0\), \(\displaystyle\lim_{i\to\infty}f_i(x) = 0\).
If \(x = 0\), \(\displaystyle\lim_{i\to\infty}f_i(x) = 1\).
\[f(x) = \begin{cases} 0 & \text{ if $x \neq 0$}\\1 & \text{ if $x = 0$}\end{cases}\]
The sequence \((f_i)\) converges to \(f\) on \((-\infty, \infty)\).
What can we say about \(f\)?
Not much!
Does not have to be continuous.
Does not have to be differentiable.
Sometimes we can say more.
Uniform Convergence
Definition: We say that a sequence of functions \((f_i)\) converges to a function \(f\)uniformly on a set \(K\) if for each \(\varepsilon > 0\) there exists an integer \(N\) such that for each \(x \in K\),\[\left\lvert f_i(x) -
f(x)\right\rvert < \varepsilon \text{ if } i \ge N\].
Note that the integer \(N\) depends only on the sequence \((f_i)\) and \(\varepsilon\), not on \(x\)!
Some Facts
If each \(f_i\) is continuous on \(K\) and the sequence \((f_i)\) converges to \(f\)uniformly on \(K\), then \(f\) is continuous.
If each \(f_i\) is differentiable on \(K\) with derivative \(f'_i\), the sequence \((f_i)\) converges to a function \(f\) on \(K\), and the sequence \((f'_i)\) converges to a function \(g\)uniformly on \(K\), then \(f\) is differentiable on \(K\), and \(f'(x) =
g(x)\) for every \(x \in K\).
If each \(f_i\) is Riemann integrable on an interval \(K=[a,b]\) and the sequence \((f_i)\) converges to \(f\)uniformly on \(K\), then \(f\) is Riemann integrable on \(K\), and \[\int_a^b f(x)\;dx = \lim_{i\to\infty}\int_a^b f_i(x)\;dx\]
Infinite Series
Given an infinite sequence of functions \(f_i\), \(i = k, k+1, \dots\), we define an infinite series of the functions \(f_i\) to be the sum \[\sum_{i=k}^\infty f_i(x).\]
The sequence of partial sums\((s_n)\), \(n = k, k+1, \dots\) is the sequence of functions defined as \[s_n(x) = \sum_{i = k}^n f_i(x).\]
If the sequence \((s_n)\)converges to a function \(s\) on a set \(E\), we say that the function \(s\) is the sum of the series, and we say that the series is convergent on the set \(E\).
\[\sum_{i=k}^\infty f_i(x) = s(x)\]
Example
\(f_i(x) = x^i\) for \(i = 0, 1, \dots\)
The series is \[\sum_{i=0}^\infty x^i\]
This is a geometric series, convergent if \(\left\lvert x\right\rvert < 1\).
The sum is \[\frac{1}{1-x}\]
\[\sum_{i=0}^\infty x^i = \frac{1}{1-x} \text{ for } -1 < x < 1\]
Example
Power Series
Let \(c_n\) for \(n = 0, 1, 2, \dots\) be a sequence of numbers, and \(a\) a number. The series of functions \[\sum_{i=0}^\infty c_n(x-a)^n = c_0 + c_1(x - a) + c_2(x-a)^2 + c_3(x-a)^3 + \cdots\] is called a power seriescentered at \(a\).
When \(a = 0\) we just get \[\sum_{i=0}^\infty c_nx^n = c_0 + c_1x + c_2x^2 + c_3x^3 + \cdots\]
Given the power series \[\sum_{i=0}^\infty c_n(x-a)^n = c_0 + c_1(x - a) + c_2(x-a)^2 + c_3(x-a)^3 + \cdots\] exactly one of the following will happen:
The series converges at \(a\) only.
The series converges on \((-\infty, \infty)\)
There is a positive number \(R\) such that the series converges on an interval with end-points \(a - R\) and \(a + R\), and diverges outside of that interval.
The number \(R\) is called the radius of convergence of the series.
Convergence of Power Series
Let \[\sum_{i=0}^\infty c_n(x-a)^n = c_0 + c_1(x - a) + c_2(x-a)^2 + c_3(x-a)^3 + \cdots\] be a power series with a positive (possibly infinite) radius of convergence \(R\). Then
The series converges absolutely on \((a - R, a+R)\).
For any positive \(r < R\), the series converges uniformly on \([a - r, a + r]\)